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Question

For the cell reaction:
$Z n (s) + C u^{2 +} (0.1 M) \to Z n^{2 +} (0.01 M) + C u (s)$
If $E^{0}$ is the standard emf of the cell at 298 K. Then which of the following is correct?

E = E^{0}

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E > E^{0}

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E < E^{0}

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E = 0

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Solution

The correct option is B $E > E^{0}$
$E = E^{0} - \frac{0.059}{2} log \frac{[Z n^{2 +}]}{[C u^{2 +}]} = E^{0} - \frac{0.059}{2} log \frac{0.01}{0.1} = E^{0} - \frac{0.059}{2} log \frac{1}{10}, E = E^{0} + 0.0295 ∴ E > E^{0}$

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Similar questions

For the cell reaction:

$Z n (s) + C u^{2 +} (0.1 M) \to Z n^{2 +} (0.01 M) + C u (s)$

If $E^{0}$ is the standard emf of the cell at 298 K, then:

C u^{2 +}

\to Z n^{2 +}

E^{0}

Z n (s) + C u^{2 +} (a q) ⇌ Z n^{2 +} (a q) + C u (s)

Z n / Z n^{2 +} (a = 0.1) / / C u^{2 +} (a = 0.01) / C u

E_{Z n^{2 +}}^{o} / Z n = - 0.762 V

E_{C u^{2 +}}^{o} / C u = + 0.337 V

298 K

Z n (s) ∣ Z n^{2 +} (a q, 0.1 M) ∥ A g^{+} (a q, 0.01 M) ∣ A g (s)

E_{Z n^{2 +} / Z n}^{0} = - 0.76 V

E_{A g^{+} / A g}^{0} = + 0.80 V

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