Question

For the chemical reaction $5B{r}^{\ominus }+Br{O}_3^{\ominus }+6H^{\oplus }\to 3B{r}_2+3H_{2}O$

Rate = $k\left[B{r}^{\ominus }\right]\left[Br{O}_3^{\ominus }\right][H^{\oplus }{]}^2$ The order of reaction with respect to $\left[B{r}^{\ominus }\right]$ is:

• A. 2
• B. 0
• C. 1
• D. none

Answer 1

The correct option is C 1

As given,

$5B{r}^{\ominus }+Br{O}_3^{\ominus }+6H^{\oplus }\to 3B{r}_2+3H_{2}O$

5 1 6

Rate = $k\left[B{r}^{\ominus }\right]\left[Br{O}_3^{\ominus }\right][H^{\oplus }{]}^2$

So molecularity and order of reaction with respect to $\left[B{r}^{\ominus }\right]$ is 5 and 1 respectively.