Question

For the circuit arrangement shown in figure, in the steady state condition charge on the capacitor is :

• A. $12\mu C$
• B. $14\mu C$
• C. $20\mu C$
• D. $18\mu C$

Answer 1

The correct option is D $18\mu C$

In steady state , the capacitor is fully charged and no current flow through the capacitor branch. Thus the equivalent circuit is shown in the figure.
using ohm's law, $12=(6+2)I\Rightarrow I=3/2=1.5A$
here the potential across capacitor $=$ potential drop across $6\Omega$ resistor.
or $V_C=6I=6\left(3/2\right)=9V$
Thus charge on capacitor is $Q=C{V}_C=2\times 9=18\mu C$