Question

For the circuit shown in figure, the capacitance measured between terminals B and Y will be

• A. $C_c+\left(\frac{C_s}{2}\right)$
• B. $C_s+\left(\frac{C_c}{2}\right)$
• C. $\frac{\left(C_s+3C_c\right)}{2}$
• D. $3C_c+2C_s$

Answer 1

The correct option is C $\frac{\left(C_s+3C_c\right)}{2}$

Given circuit can be redrawn as:


$C_{BY}=\frac{C_s+C_c}{2}+C_c=\frac{C_s+3C_c}{2}$