Question

For the equation $3x^2+px+3=0$, the roots are real and 1 root is the square of the other, Find p?

• A. -3
• B. -1
• C. -6
• D. 2/3

Answer 1

The correct option is C -6

Let the roots of the given equation be a and $a^2$.

Sum of the roots $(a+a^2)=\frac{-P}{3}.........\left(1\right)$

Product of the roots $(a{)}^3=1\Rightarrow a=1$

From equation (1),

$1+1=\frac{-P}{3}\Rightarrow P=-6$