Question

For the equation $3x^2+px+3=0,p>0$ if one root is the square of the other then p is equal to

• A. $\frac{1}{3}$
• B. 1
• C. 3
• D. $\frac{2}{3}$

Answer 1

The correct option is C 3

$\alpha +{\alpha }^2=-p/3$ and $\alpha .{\alpha }^2=1$
If $\omega ,{\omega }^2$ are the imaginary roots of the quadratic equation $x^2+x+1=0$ then ${\omega }^3=1$ and $\omega +{\omega }^2-1$
$\Rightarrow p=3$