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For the gaseous reactions:
A(g)3B(g)    :KP1and  P(g)2Q(g)+R(g);     KP2
Occuring in two different vessels at the same temperature, the degree of dissociation of A and P are same when the total equilibrium pressure of gases in both vessels are same. If KP1:KP2 is X:4, then value of "X" is
 


Solution

A(g)3B(g);   KP1
1                 01α         3αAt equilibriumKP1=(3α)3(1α)P2(1+2α)2P(g)2Q(g)+R(g);   KP2
1α        2α          αat equilibrium KP2=(2α)2α(1α)P2(1+2α)2KP1KP2=X4=33α3P2(1α)(1+2a)24α3P2(1α)(1+2α)2 X=27

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