Question

For the given reaction,

$3Fe\left(s\right)+x{H}_{2}O\left(l\right)\to F{e}_3{O}_4\left(s\right)+4H_2\left(l\right)$

What should be the values of x so that it is balanced?

• A. 4

Answer 1

The correct option is A 4
A balanced chemical equation has an equal number of atoms of each element in reactants and products.

Consider the coefficients of Fe as 'A', ${\text{H}}_2\text{O}$ as 'B', ${\text{Fe}}_3{\text{O}}_4$ as 'C' and ${\text{H}}_2$ as 'D'.
Given, A = 3, C = 1 and D = 4
By shortcut method, 2B = 2D
2B = 2$\times$4
$⟹$B = 4
Since, B = $x$ Therefore, $x$ = 4