Question

For the hypothetical reactions, the equilibrium constant (K) values are given:
$A\rightleftharpoons B;K_1=2;B\rightleftharpoons C;K_2=4;C\rightleftharpoons D;K_3=3$
The equilibrium constant (K) for the reaction $A\rightleftharpoons D$ is:

• A. 48
• B. 6
• C. 24
• D. 12

Answer 1

The correct option is C 24

On adding the reaction , the equilibrium constant get multiplied.
The reaction $A\rightleftharpoons D$ is obtained by adding the three given reactions.
$\therefore K=K_1\times K_2\times K_3$
$K=2\times 4\times 3=24$
Hence, correct option is c