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Standard XII

Chemistry

Derivation of Kp and Kc

For the hypot...

Question

For the hypothetical reactions, the equilibrium constant (K) values are given:
$A ⇌ B; K_{1} = 2; B ⇌ C; K_{2} = 4; C ⇌ D; K_{3} = 3$
The equilibrium constant (K) for the reaction $A ⇌ D$ is:

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Solution

The correct option is C 24
On adding the reaction , the equilibrium constant get multiplied.
The reaction $A ⇌ D$ is obtained by adding the three given reactions.
$∴ K = K_{1} \times K_{2} \times K_{3}$
$K = 2 \times 4 \times 3 = 24$
Hence, correct option is c

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Similar questions

Q. For the hypothetical reactions, the equilibrium constant (K) values are given:

A ⇌ B; K_{1} = 2; B ⇌ C; K_{2} = 4; C ⇌ D; K_{3} = 3

The equilibrium constant (K) for the reaction

A ⇌ D

is:

Q. For a reactions, the equilibrium constant

(K)

values are given:

A ⇌ B; K_{1} = 2 B ⇌ C; K_{2} = 4 C ⇌ D; K_{3} = 3

Then calculate the equilibrium constant for the reaction

A ⇌ D

Q. For the hypothetical reaction, the equilibrium constant (k) values are given

A \to B (k = k_{1}) B \to C (k = k_{2}) C \to D (k = k_{3})

What is the value of equilibrium constant for

A \to D

Q. For the reactions,

A ⇌ B, B ⇌ C, C ⇌ D

, equilibrium constants are

K_{1}, K_{2}, K_{3}

respectively.

What is the value of the equilibrium constant for

A ⇌ D

The equilibrium constants for the reactions are:

$H_{3} P O_{4}_{1} H^{+} + H_{2} P O_{4}^{-}; K_{1} H_{2} P O_{4}^{-}_{2} H^{+} + H P O_{4}^{2 -}; K_{2} H P O_{4}^{2 -}_{3} H^{+} + P O_{4}^{3 -}; K_{3}$

The equilibrium constant for, $H_{3} P O_{4} ⇌ 3 H^{+} + P O_{4}^{3 -}$ will be:

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Derivation of Kp and Kc

Standard XII Chemistry

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For the hypothetical reactions, the equilibrium constant (K) values are given: A⇌B;K1=2;B⇌C;K2=4;C⇌D;K3=3 The equilibrium constant (K) for the reaction A⇌D is:

The correct option is C 24On adding the reaction , the equilibrium constant get multiplied. The reaction A⇌D is obtained by adding the three given reactions. ∴ K=K1×K2×K3 K=2×4×3=24 Hence, correct option is c

For the hypothetical reactions, the equilibrium constant (K) values are given:
$A ⇌ B; K_{1} = 2; B ⇌ C; K_{2} = 4; C ⇌ D; K_{3} = 3$
The equilibrium constant (K) for the reaction $A ⇌ D$ is:

The correct option is C 24
On adding the reaction , the equilibrium constant get multiplied.
The reaction $A ⇌ D$ is obtained by adding the three given reactions.
$∴ K = K_{1} \times K_{2} \times K_{3}$
$K = 2 \times 4 \times 3 = 24$
Hence, correct option is c