For the potentiometer arrangement shown in the figure, length of wire AB is 100 cm and its resistance is 9Ω. The length AC for which the galvanometer G will show zero deflection is
Potential difference across AC is zero as
IAC=0
5 – 2l = 0
I = 2.5 A
Let the resistance of part BC be r
Applying KVL
10 + 5 – 2l – lr – l = 0
2.5r = 7.5 ⇒ r=3Ω
As resistance of part AB = 9Ω
∴ length AC = 66.7 cm