Question

For the reaction $2N_2{O}_{5\left(g\right)}\to 4{NO}_{2\left(g\right)}+O_{2\left(g\right)}$ in liquid bromine, which of the following rate equation is incorrect?

• A. $-\frac{1}{2}\frac{d\left[N_2{O}_5\right]}{dt}$
• B. $-\frac{1}{4}\frac{d\left[{NO}_2\right]}{dt}$
• C. $\frac{d\left[O_2\right]}{dt}$
• D. $\frac{1}{4}\frac{d\left[{NO}_2\right]}{dt}$

Answer 1

The correct option is B $-\frac{1}{4}\frac{d\left[{NO}_2\right]}{dt}$

In liquid $B{r}_2$ the reaction stiochiometry allows 4 equivalent of $N_2{O}_5$ to react thus

$\vartheta =\frac{-1}{4}\frac{d\left[N_2{O}_5\right]}{dt}$