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Byju's Answer
Standard VII
Chemistry
Rate of Reaction
For the react...
Question
For the reaction,
2
N
2
O
5
⟶
4
N
O
2
+
O
2
the rate of reaction is:
A
1
2
d
d
t
[
N
2
O
5
]
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B
2
d
d
t
[
N
2
O
5
]
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C
1
2
d
d
t
[
N
O
2
]
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D
4
d
d
t
[
N
O
2
]
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Solution
The correct option is
C
1
2
d
d
t
[
N
O
2
]
For the reaction,
2
N
2
O
5
⟶
4
N
O
2
+
O
2
the rate of reaction is
1
2
d
d
t
[
N
O
2
]
Rate of reaction
−
1
2
d
[
N
2
O
5
]
d
t
=
1
4
d
[
N
O
2
]
d
t
Suggest Corrections
0
Similar questions
Q.
For the reaction,
N
2
O
5
⟶
2
N
O
2
+
1
/
2
O
2
,
−
d
[
N
2
O
5
]
d
t
=
k
1
[
N
2
O
5
]
d
[
N
O
2
]
d
t
=
k
2
[
N
2
O
5
]
d
[
O
2
]
d
t
=
k
3
[
N
2
O
5
]
The relation in between
k
1
,
k
2
and
k
3
is:
Q.
For the reaction;
N
2
O
5
⟶
2
N
O
2
+
1
2
O
2
,
given:
−
d
[
N
2
O
5
]
d
t
=
K
1
[
N
2
O
5
]
−
d
[
N
O
2
]
d
t
=
K
2
[
N
O
2
]
,
and
−
d
[
O
2
]
d
t
=
K
3
[
O
2
]
The relation between
K
1
,
K
2
,
K
3
is:
Q.
For the reaction,
N
2
O
5
→
2
N
O
2
+
1
2
O
2
.
G
i
v
e
n
:
−
d
[
N
2
O
5
]
d
t
=
K
1
[
N
2
O
5
]
d
[
N
O
2
]
d
t
=
K
2
[
N
2
O
5
]
A
n
d
d
[
O
2
]
d
t
=
K
3
[
N
2
O
5
]
The relation between
K
1
,
K
2
and
K
3
is
Q.
For
N
2
O
5
→
2
N
O
2
+
1
2
O
2
,
it is found that
−
d
d
t
[
N
2
O
5
]
=
k
1
[
N
2
O
5
]
,
d
d
t
[
N
O
2
]
=
k
2
[
N
2
O
5
]
a
n
d
d
d
t
[
O
2
]
=
k
3
[
N
2
O
3
]
,
then:
Q.
The rate of the reaction
2
N
2
O
5
⟶
4
N
O
2
+
O
2
can be written in three ways:
−
d
[
N
2
O
5
]
d
t
=
k
[
N
2
O
5
]
d
[
N
O
2
]
d
t
=
k
′
[
N
2
O
5
]
d
[
O
2
]
d
t
=
k
′
′
[
N
2
O
5
]
The relationship between
k
and
k
′
and between
k
and
k
′
′
are :
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