Question

For the reaction, $2N_2{O}_5⟶4N{O}_2+O_2$ rate of reaction is___________.

• A. $\frac{1}{2}\frac{d}{dt}\left[N_2{O}_5\right]$
• B. $2\frac{d}{dt}\left[N_2{O}_5\right]$
• C. $\frac{1}{4}\frac{d}{dt}\left[N{O}_2\right]$
• D. $4\frac{d}{dt}\left[N{O}_2\right]$

Answer 1

The correct option is C $\frac{1}{4}\frac{d}{dt}\left[N{O}_2\right]$

$\vartheta =\frac{-1}{2}\frac{d\left[N_2{O}_5\right]}{dt}=\frac{1}{4}\frac{d\left[N{O}_2\right]}{dt}=\frac{d\left[O_2\right]}{dt}$