For the reaction A+2B ⇌ C, the expression for equilibrium constant is
([A][B]2)/[C]
([A][B])/[C]
[C]/([A][B]2)
[C]/(2[B][A])
The equilibrium constant will be [C][A][B]2
For the system 3A + 2B ⇌ C, the expression for equilibrium constant is
For the reaction A + B ⇋ C + D the equilibrium constant is