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Question

For the reaction A+2B C, the expression for equilibrium constant is


A

([A][B]2)/[C]

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B

([A][B])/[C]

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C

[C]/([A][B]2)

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D

[C]/(2[B][A])

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Solution

The correct option is C

[C]/([A][B]2)


The equilibrium constant will be [C][A][B]2


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