For the reaction
$C u S O_{4} .5 H_{2} O_{(s)} ⇌ C u S O_{4} .3 H_{2} O_{(s)} + 2 H_{2} O_{(g)}$
Which one is correct representation :-

K_{p} = {(P_{(H_{2} O)})}^{2}

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K_{c} = {[H_{2} O]}^{2}

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K_{p} = K_{c} {(R T)}^{2}

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Solution

The correct option is D All
For the reaction
$C u S O_{4} .5 H_{2} O_{(s)} ⇌ C u S O_{4} .3 H_{2} O_{(s)} + 2 H_{2} O_{(g)}$
The correct representations are
(A) $K_{p} = {(P_{(H_{2} O)})}^{2}$
(B) $K_{c} = {[H_{2} O]}^{2}$
(C) $K_{p} = K_{c} {(R T)}^{2}$
$K_{p} = K_{c} {(R T)}^{Δ n}$ and $Δ n = 2$
Note: The concentrations of the solid substances do not appear in the equilibrium constant expression.

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Similar questions

C u {S O}_{4} \cdot 5 H_{2} O_{(s)} ⇌ {C u S O}_{4} \cdot {3 H}_{2} O_{(s)} + {2 H}_{2} O_{(g)}

K_{p} = {(P_{(H_{2} O)})}^{2}

K_{c} = {(H_{2} O)}^{2}

K_{p} = K_{c} {(R T)}^{2}

2 H_{2} O_{(g)} + 2 {C l}_{2 (g)} ⟶ 4 H {C l}_{(g)} + O_{2 (g)}

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K_{c}

K_{p} = K_{c}

K_{p}

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K_{p} = K_{c}

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