For which reaction $K_{p} = K_{c}$ ?

2 N O C l (g) ⇌ 2 N O (g) + C l_{2} (g)

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N_{2} (g) + 3 H_{2} (g) ⇌ 2 N H_{3} (g)

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H_{2} (g) + I_{2} (g) ⇌ 2 H I (g)

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2 S O_{2} (g) + O_{2} (g) ⇌ 2 O_{3} (g)

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Solution

The correct option is D $H_{2} (g) + I_{2} (g) ⇌ 2 H I (g)$
We know that
$K p = K c (R T)^{Δ n}$
if $Δ n = 0$ , then
$K p = K c$
In equation (c), $H_{2} (g) + I_{2} (g) ⇌ 2 H I (g)$
Here $Δ n (g)$ = product - reactant
$= 2 - 2$
$= 0$
So, $C$ option is correct

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Similar questions

2 H I_{(g)} ⟶ H_{2 (g)} + I_{2 (g)}

2 N H_{3 (g)} ⟶ N_{2 (g)} + 3 H_{2 (g)}

2 N O_{(g)} ⟶ N_{2 (g)} + O_{2 (g)}

P C l_{5 (g)} ⟶ P C l_{3 (g)} + C l_{2 (g)}

log \frac{K_{p}}{K_{c}} + log R T = 0

log \frac{K_{P}}{K_{C}} + log R T = 0

K_{p}

K_{c}

\frac{K_{p}}{K_{c}}

300 K

N_{2} (g) + O_{2} (g) ⇌ 2 N O (g)

N_{2} O_{4} (g) ⇌ 2 N O_{2} (g)

N_{2} (g) + 3 H_{2} (g) ⇌ 2 N H_{3} (g)

[A t 300 K, R T = 24.62 d m^{3} a t m m o l^{- 1}]

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