Question

For the stationary wave y= 4 sin( $\pi x$/15) cos(96 $\pi$ t) the distance between a node and the next antinode is

• A. 7.5
• B. 15
• C. 22.5
• D. 30

Answer 1

The correct option is A

7.5

On comparing

$Kx=\frac{\pi x}{15}K=\frac{\pi }{15}\Rightarrow =\frac{2\pi }{\lambda }=\frac{\pi }{15}\Rightarrow \lambda =30$
Distance between a node and the next anti-node is $\frac{\lambda }{4}$

$\frac{\lambda }{4}$ = $\frac{30}{4}=7.5$