Question

For what value of k will k + 9, 2k – 1 and 2k + 7 are the consecutive terms of an A.P.?

Answer 1

$$\begin{gathered} DearStudent, \\ ForsequencetobeinAP\hspace{0.17em},differenceshouldbesame. \\ (2k-1)-(k+9)=(2k+7)-(2k-1) \\ \Rightarrow 2k-1-k-9=2k+7-2k+1 \\ \Rightarrow k-10=8 \\ \Rightarrow k=18 \\ Regards \end{gathered}$$