Four 60 W - 230 V bulbs are connected between the phase and the neutral as shown in the diagram- Line voltage is 230 V-A- B 3- B 4 are in parallelB 1- B 2 are in seriesB- B 3- B 4 are in seriesB 1- B 2 are in seriesC- B 3- B 4 are in seriesB 1- B 2 are in parallelD- B 3- B 4 are in parallelB 1- B 2 are in parallel

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Physics

Electric Power

Four 60 W , 2...

Question

Four 60 W, 230 V bulbs are connected between the phase and the neutral as shown in the diagram. Line voltage is 230 V.

How are the bulbs $B_{3} a n d B_{4}$ and $B_{1} a n d B_{2}$ connected?

$B_{3}, B_{4}$ are in series
$B_{1}, B_{2}$ are in parallel

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$B_{3}, B_{4}$ are in parallel
$B_{1}, B_{2}$ are in series

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$B_{3}, B_{4}$ are in series
$B_{1}, B_{2}$ are in series

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$B_{3}, B_{4}$ are in parallel
$B_{1}, B_{2}$ are in parallel

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Solution

The correct option is A
$B_{3}, B_{4}$ are in series
$B_{1}, B_{2}$ are in parallel

The current flowing through $B_{3}$ is equal to that flowing through the $B_{4}$ . Therefore, $B_{3}$ and $B_{4}$ are in series.
The voltage across $B_{1}$ and $B_{2}$ are equal since they have two common points. Hence, they are in parallel connection.

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Similar questions

Q. Suppose four distinct positive numbers

a_{1}, a_{2}, a_{3}, a_{4}

are in

G . P

. Let

b_{1} = a_{1}, b_{2} = b_{1} + a_{2}, b_{3} = b_{2} + a_{3}

and

b_{4} = b_{3} + a_{4}

.
STATEMENT-1 : The numbers

b_{1}, b_{2}, b_{3}, b_{4}

are neither in

A . P

. nor in

G . P

.
STATEMENT-2 : The numbers

b_{1}, b_{2}, b_{3}, b_{4}

are in

H . P

Q. Assertion :Suppose four distinct positive numbers

a_{1}, a_{2}, a_{3}, a_{4}

are in GP. Let

b_{1} = a_{1}, b_{2} = b_{1} + a_{2}, b_{3} = b_{2} + a_{3}

and

b_{4} = b_{3} + a_{4} .

STATEMENT- 1: The numbers

b_{1}, b_{2}, b_{3}, b_{4}

are neither in AP nor in GP, and Reason: STATEMENT- 1: The numbers

b_{1}, b_{2}, b_{3}, b_{4}

are in HP.

Q. Suppose four distinct positive number

a_{1}, a_{2}, a_{3}, a_{4}

are in G.P. Let

b_{1} = a_{1}, b_{2} = b_{1} + a_{2}, a_{3} = b_{2} + a_{3}

and

b_{4} = b_{3} + a_{4}

Statement 1 - The numbers

b_{1}, b_{2}, b_{3}, b_{4}

are neither in A.P. nor in G.P.
Statement 2 - The numaber

b_{1}, b_{2}, b_{3}, b_{4}

are in H.P.

Four 60 W, 230 V bulbs are connected between the phase and the neutral as shown in the diagram. Line voltage is 230 V.

Which bulb/bulbs will glow at 60 W power?

Q. If

b_{1}, b_{2}, b_{3}, . . . b_{n}

are in H.P then

b_{1} b_{2} + b_{2} b_{3} + b_{3} b_{4} + . . . + b_{n - 1} b_{n} =

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Four 60 W, 230 V bulbs are connected between the phase and the neutral as shown in the diagram. Line voltage is 230 V. How are the bulbs B3 and B4 and B1 and B2 connected?

The correct option is A B3, B4 are in series B1, B2 are in parallel The current flowing through B3 is equal to that flowing through the B4. Therefore, B3 and B4 are in series. The voltage across B1 and B2 are equal since they have two common points. Hence, they are in parallel connection.

Four 60 W, 230 V bulbs are connected between the phase and the neutral as shown in the diagram. Line voltage is 230 V.

How are the bulbs $B_{3} a n d B_{4}$ and $B_{1} a n d B_{2}$ connected?