Question

Four containers can hold $101liters$ of milk .

(a)how much milk will $7$ containers hold

Answer 1

Given. Four containers can hold $=101liters$

$7$ containers can hold $=kliters$

As the time decreases, the distance also increases in the same ratio. It is a case of direct proportion.

We make use of the relation of type $\frac{x_1}{x_2}=\frac{y_1}{y_2}$

Suppose the number of containers is $\text{'}x\text{'}$ number of liters is $\text{'}y\text{'}.$.

$$\begin{gathered} x_1=4;x_2=7 \\ {y}_1=101liters;y_2=kliters \end{gathered}$$

$$\begin{gathered} \frac{4}{7}=\frac{101}{k} \\ 4\times k=101\times 7 \\ k=\frac{{\displaystyle \stackrel{25.25}{\cancel{101}}}\times {\displaystyle 7}}{{\displaystyle \underset{\cancel{1}}{4}}} \\ k=176.75liters \end{gathered}$$

Hence the $7$ containers can hold is $176.75liters$