Four identical cells of emf E and internal resistance r are to be connected in series. Suppose if one of the cell is connected wrongly, the equivalent emf and effective internal resistance of the combination is
A
4E and 4r
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B
4E and 2r
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C
2E and 4r
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D
2E and 2r
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Solution
The correct option is D2E and 4r Equivalent resistance in series connection req=r1+r2+r3+r4
∴req=r+r+r+r=4r
Equivalent emf in series connection Eeq=E1+E2+E3−E4 (as one is connected wrong)