Four point masses, each of value m, are placed at the corners of square ABCD of side l. The moment of inertia of this system about an axis passing through A and parallel to BD is
A
3ml2
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B
ml2
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C
2ml2
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D
√3ml2
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Solution
The correct option is A 3ml2 Moment of inertia of system I=IA+IB+IC+ID ⇒I=0+m(AO)2+m(AO)2+m(AC)2 AO cos 45o=l2⇒AO=1√2