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Byju's Answer
Standard XII
Chemistry
Nernst Equation
Give Nernst e...
Question
Give Nernst equation:
Calculate the electrode potential of the following single electrode.
C
u
+
+
(
a
q
)
(
C
=
0.01
M
)
/
C
u
;
(
E
∘
=
+
0.337
V
)
Open in App
Solution
The Nernst equation is:
E
e
l
=
E
0
e
l
−
0.0592
n
l
o
g
Q
For the given electrode,
C
u
2
+
+
2
e
−
→
C
u
E
e
l
=
E
0
e
l
−
0.0592
n
l
o
g
1
[
C
u
2
+
]
E
e
l
=
+
0.337
V
−
0.0592
2
l
o
g
1
0.01
E
e
l
=
+
0.278
V
Suggest Corrections
0
Similar questions
Q.
The electrode potentials for
C
u
2
+
(
a
q
)
+
e
−
→
C
u
+
(
a
q
)
and
C
u
+
(
a
q
)
+
e
−
→
C
u
(
s
)
Are
+
0.15
V
and
+
0.50
V
respectively.
The value of
E
∘
C
u
2
+
/
C
u
will be
Q.
1.
C
u
2
+
+
2
e
−
⟶
C
u
,
E
0
=
0.337
V
2.
C
u
2
+
+
e
−
⟶
C
u
+
,
E
0
=
0.153
V
Electrode potential,
E
0
for the reaction
C
u
+
+
e
−
⟶
C
u
Q.
The electrode potential for
C
u
2
+
(
a
q
)
+
e
−
→
C
u
+
(
a
q
)
and
C
u
+
(
a
q
)
+
e
−
→
C
u
(
s
)
are +0.15 V and +0.50 V respectively. The value of
E
o
C
u
2
+
/
C
u
will be:
Q.
Given (i)
C
u
2
+
+
2
e
−
→
C
u
,
E
o
=
+
0.337
V
(ii)
C
u
2
+
+
e
−
→
C
u
+
E
o
=
+
0.153
V
Electrode potential,
E
0
for the reaction will be:
C
u
+
+
e
−
→
C
u
Q.
The cell reaction in Daniel cell is
Z
n
(
s
)
+
C
u
2
+
(
a
q
)
→
Z
n
2
+
(
a
q
)
+
C
u
(
s
)
and Nernst equation for single electrode potential for general electrode reaction
M
n
+
(
a
q
)
+
n
e
−
→
M
(
s
)
is
E
M
n
+
/
M
=
E
o
M
n
+
/
M
−
2.303
R
T
n
F
l
o
g
[
M
]
[
M
n
+
]
Derive Nernst equation for Daniel Cell.
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