Give reasons of the following:
$C H_{3} N H_{2}$ is more basic than $C_{6} H_{5} N H_{2}$

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Solution

In aniline lone pair present on nitrogen is in resonance with the benzene ring. Hence due to delocalisation of lone pair present on nitrogen basicity of aniline decreases.

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Arrange the following in increasing order of their basic strength:

(i) C₂H₅NH₂, C₆H₅NH₂, NH₃, C₆H₅CH₂NH₂ and (C₂H₅)₂NH

(ii) C₂H₅NH₂, (C₂H₅)₂NH, (C₂H₅)₃N, C₆H₅NH₂

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C_{6} H_{5} N H_{2}

N H_{2}

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