Question

Give the iupac names

[Pt(NH3)4][PtCl4]

[Pt(NH3)4Cl2][PtCl4]

Answer 1

[Pt(NH3)4 Cl2] [PtCl4]

The IUPAC name of the given compound should be:

Tetraaminedichloroplatinum(IV) tetrachloroplatinate(II)

Firstly, we write the name of the cationic part of the coordinate compound i.e. [Pt(NH3)4Cl2]:

Here, the ligands are Amine and Chloride. Since, there are 4 amine groups we’ll name it as tetraamine and 2 chloride groups will be named as dichloro. Also, we have platinum metal as the central metal atom in a cation so we keep it’s name as platinum and it’s oxidation state +4 in roman numerics in paranthesis “()”.

The arrangement of the names will be in the order: name of ligands mentioned in alphabetical order of their first letter( while ordering alphabetically, don’t consider the the suffixes - di, tri, tetra, penta, etc in the order).

Now for the anionic part:

Here the ligand is chloride. Since, there are 4 chlorides so the we’ll call it tetrachloride. We have the central metal atom as platinum again, but since it is in the anionic coordination sphere we will name it as platinate followed by the oxidation state, +2, in parenthesis (in roman numerals).


[Pt(NH3)4][PtCl4]
Tetraammineplatinum(II) tetrachloroplatinate(II)