Question

Given $\left[\begin{array}{cc}x& y+2\\ 3& z-1\end{array}\right]=\left[\begin{array}{cc}3& 1\\ 3& 2\end{array}\right]$; then find the value of x+y +z.

• A. 6
• B. 4
• C. 5
• D. 8

Answer 1

The correct option is C 5

$\left[\begin{array}{cc}x& y+2\\ 3& z-1\end{array}\right]=\left[\begin{array}{cc}3& 1\\ 3& 2\end{array}\right]$

x=3
y+2=1
y=-1
z-1=2
z=3
So, x+y+z = 3+(-1)+3 = 5.