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Question

Given standard electrode potentials, Fe2+2eFe, E=0.440 V
Fe3++3eFe, E=0.036 V

The standard electrode potential (E) for Fe3++eFe2+ is:

A
+0.772 V
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B
0.772 V
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C
+0.417 V
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D
0.414 V
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Solution

The correct option is B +0.772 V
We know, G=nFE

Fe2++2eFe

G=2×F×(0.440V)=0.880 F ...... (1)

Fe3++3eFe

G=3×F×(0.036) =0.108 F----------(2)

On subtracting Eqs. (1) from (2),Fe3++eFe2+

G=0.108F0.880F=0.772F

ΔGo=nFEo

E=GnF=0.772F1×F=+0.772V

Hence, the correct option is A.

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