CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Given sublimation and ionization energy of Na are 108 kJ/mol and 496 kJ/mol respectively and bond dissociation energy required to make one mole chlorine atoms and its electron affinity energy are 122 kJ/mol and -349 kJ/mol.If H0f of NaCl(s) is -411 kJ/mol.What is its approximate lattice formation enthalpy?

A
286 kJ/mol
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
-788 kJ/mol
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
388 kJ/mol
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
-508 kJ /mol
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B -788 kJ/mol
We can use Born Haber cycle to find lattice energy
H0f = Hsub+ IE +Hdiss + EA + U = 108+496+122-349+ U=-411kJ/mol
U = -788 kJ/mol

flag
Suggest Corrections
thumbs-up
7
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon