Given that y - cx - d - bthen- what is the value of x- in a x-b y-c-0 if b-0 -a-c-0A- d-c1-C- -d-c-a-cD- None

The correct option is C ( d c)/(a + c)Given: ax + by + c = 0, Also given y=(cx+d)/b, substitute this in ax + by + c = 0 We get ax + [b (cx + d)/b] + c = 0 ...

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Standard IX

Mathematics

Solving Equations Using Method of Substitution

Given that y ...

Question

$G i v e n t h a t y = \frac{(c x + d)}{b}$ ;

then, what is the value of x, in $a x + b y + c = 0$

if $b \neq 0 & (a + c) \neq 0$ ,

\frac{(d + c)}{(a + c)}

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\frac{(- d - c)}{(a + c)}

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\frac{(a + c)}{(d + c)}

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None

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Solution

The correct option is B $\frac{(- d - c)}{(a + c)}$
$G i v e n : a x + b y + c = 0,$
Also given $y = \frac{(c x + d)}{b}$ , substitute this in $a x + b y + c = 0$
$W e g e t a x + [b \frac{(c x + d)}{b}] + c = 0$
$S o, a x + c x + d + c = 0$
$(a + c) x = - d - c$
$T h e r e f o r e, x = \frac{(- d - c)}{(a + c)}$ .

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Given that y=(cx+d)b; then, what is the value of x, in ax+by+c=0 if b≠0 & (a+c)≠0,

The correct option is B (−d−c)(a+c)Given: ax+by+c=0, Also given y=(cx+d)b, substitute this in ax+by+c=0 We get ax+[b(cx+d)b]+c=0 So, ax+cx+d+c=0 (a+c)x=−d−c Therefore, x=(−d−c)(a+c).

$G i v e n t h a t y = \frac{(c x + d)}{b}$ ;

then, what is the value of x, in $a x + b y + c = 0$

if $b \neq 0 & (a + c) \neq 0$ ,