Given that- y - cx - d - b - where- b -0 - a - c -0then- what is the value of x- if a x-b y-c-0 -A- d-c-a-cB- -d-c-a-cC- NoneD- a-c-d-c

The correct option is B ( d c)/(a + c)Given ax + by + c = 0, Also given, y=(cx+d)/b, substitute this in ax + by + c = 0 We get, ax + [b (cx + d)/b] + c = 0 ...

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Standard IX

Mathematics

Substitution Method

Given that, y...

Question

Given that,
$y = \frac{(c x + d)}{b}$ ; where, $b \neq 0 & (a + c) \neq 0$ ,

then, what is the value of x, if $a x + b y + c = 0 ?$

\frac{(d + c)}{(a + c)}

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\frac{(- d - c)}{(a + c)}

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\frac{(a + c)}{(d + c)}

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None

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Solution

The correct option is B $\frac{(- d - c)}{(a + c)}$
Given $a x + b y + c = 0,$
Also given,
$y = \frac{(c x + d)}{b}$ ,
substitute this in $a x + b y + c = 0$
We get,
$a x + [b \frac{(c x + d)}{b}] + c = 0$
$a x + c x + d + c = 0$
$(a + c) x = - d - c$
Therefore,
$x = \frac{(- d - c)}{(a + c)}$

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Given that, y=(cx+d)b; where, b≠0 & (a+c)≠0, then, what is the value of x, if ax+by+c=0?

The correct option is B (−d−c)(a+c)Given ax+by+c=0, Also given, y=(cx+d)b, substitute this in ax+by+c=0 We get, ax+[b(cx+d)b]+c=0 ax+cx+d+c=0 (a+c)x=−d−c Therefore, x=(−d−c)(a+c)

Given that,
$y = \frac{(c x + d)}{b}$ ; where, $b \neq 0 & (a + c) \neq 0$ ,

then, what is the value of x, if $a x + b y + c = 0 ?$

The correct option is B $\frac{(- d - c)}{(a + c)}$
Given $a x + b y + c = 0,$
Also given,
$y = \frac{(c x + d)}{b}$ ,
substitute this in $a x + b y + c = 0$
We get,
$a x + [b \frac{(c x + d)}{b}] + c = 0$
$a x + c x + d + c = 0$
$(a + c) x = - d - c$
Therefore,
$x = \frac{(- d - c)}{(a + c)}$