Given the area of rectangle is A=25a2−45a+18. The length is given as (5a−3). Therefore, the width is:
5a - 3
Let y be the width.
Since area is given as 25a2−45a+18 which is the product of y and (5a−3), we have
y(5a−3)=25a2−45a+18
To find y, we need to do a long division of 25a2–45a+18 by (5a-3).
5a−35a−6√25a2−45a+18 25a2−15a − + ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯ −30a+18 −30a+18 + − ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯ 0
∴y=5a−6