wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Given the area of rectangle is A=25a245a+18. The length is given as (5a3). Therefore, the width is:


A

5a - 3

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B

5a - 4

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

4a - 5

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

a - 4

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A

5a - 3


Let y be the width.
Since area is given as 25a245a+18 which is the product of y and (5a3), we have
y(5a3)=25a245a+18
To find y, we need to do a long division of 25a245a+18 by (5a-3).
5a35a625a245a+18 25a215a + ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯ 30a+18 30a+18 + ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯ 0
y=5a6


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Algebraic Identities
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon