Question

Graph between $\log \left(\frac{x}{m}\right)$ and $\log p$ is a straight line at an angle ${45}^{\circ }$ with intercept on y-axis $0,3010$. Calculate the amount of gas adsorbed in gram per gram of the adsorbent when pressure is $0.2atm$.

• A. $0.4$
• B. $0.6$
• C. $0.8$
• D. $0.2$

Answer 1

The correct option is A $0.4$

$log\left(\frac{x}{m}\right)=logK+\frac{1}{x}logP$

Inclined angle of straight line is ${45}^0$.

$\therefore \frac{1}{x}={tan45}^0=1$

now, $logK=0.3\Rightarrow K=2$

now $\frac{x}{m}=K{P}^{1/x}=2\times {\left(02\right)}^1(P=0.2atm)$

$=0.4$