$H_{2} O_{2} \to 2 H^{+} + O_{2} + 2 e^{-}$
The above equation represent which of the following behaviour of $H_{2} O_{2}$ ?

Reducing

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Oxidising

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Basic

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Catalytic

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Solution

The correct option is D Reducing
$H_{2} O_{2} \to 2 H^{+} + O_{2} + 2 e^{-}$ , in this reaction water is giving two electrons, which is used for reduction.

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