Question

Hamid has three boxes of different fruits. Box $A$ weights $2\frac{1}{2}kg$ more than Box $B$ and Box $C$ weights $10\frac{1}{4}kg$ more than Box $B$. The total weight of the boxes is $48\frac{3}{4}$. How many $kgs$ does Box A weights?

• A. $15\frac{1}{2}kg$
• B. $14\frac{1}{2}kg$
• C. $13\frac{1}{2}kg$
• D. $noneofthese$

Answer 1

The correct option is B $14\frac{1}{2}kg$

Let weight of $B=x$

$\Rightarrow$ Weight of $A=x+2\frac{1}{2}$

$=x+\frac{5}{2}$

$\Rightarrow$ Weight of $C=x+10\frac{1}{4}$

$=x+\frac{41}{4}$

Total weight of bottles is $48\frac{3}{4}=\frac{195}{4}$

$\Rightarrow x+x+x+\frac{5}{2}+\frac{41}{4}=\frac{195}{4}$

$\Rightarrow 3x+\frac{41+10}{4}=\frac{195}{4}$

$\Rightarrow 3x+\frac{51}{4}=\frac{195}{4}$

$\Rightarrow 3x=\frac{195}{4}-\frac{51}{4}$

$\Rightarrow 3x=\frac{144}{4}$

$\Rightarrow 3x=36$

$\Rightarrow x=12$
$\therefore$ Weight of $B=12kg$

And weight of $A=12+\frac{5}{2}=14.5kg$