Question

Heat required to convert 1 g of ice at $0^{0}C$ into steam at ${100}^{0}C$ is ( $L_{Steam}=536cal/g$ ) :

• A. 100 cal
• B. 0.01 kilo calorie
• C. 716 cal
• D. 1 kilo calorie

Answer 1

The correct option is C 716 cal

First the ice at $0^o$C should be converted to water at $0^o$C, then to water at ${100}^o$C and then to steam at ${100}^o$C.
Total heat required $=m{L}_i+mc\Delta T+m{L}_e$
$=1[80+1(100-0)+536]=716cal$