How many bricks of size $22 c m \times 10 c m \times 7 c m$ are required to construct a wall 11 m long, 3.5 m high and 40 cm thick, if the cement and sand used in the construction occupy $(\frac{1}{10}) t h$ part of the wall?

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Solution

Volume of each brick $= 22 c m \times 10 c m \times 7 c m$
$= 1540 c m^{3} = 0.00154 m^{3}$
Volume of wall $= l \times b \times h = 11 m \times 3.5 m \times \frac{40}{100} m$ [ $∵$ 1m = 100 cm]
$= 11 \times 3.5 \times 0.4 = 15.4 m^{3}$
If $\frac{1}{10} t h$ part of the wall used in cement and sand, then part of wall used by cement and sand $= \frac{15.4}{10} m^{3} = 1.54 m^{3}$
Remaining part $= 15.4 - 1.54 = 13.86 m^{3}$
Number of bricks $= \frac{V o l u m e o f w a l l t o b e c o n s t r u c t}{V o l u m e o f e a c h b r i c k} = \frac{13.86}{0.00154} = 9000$

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How many bricks of size 22 cm×10 cm×7 cm are required to construct a wall 11 m long, 3.5 m high and 40 cm thick, if the cement and sand used in the construction occupy (110)th part of the wall?

How many bricks of size $22 c m \times 10 c m \times 7 c m$ are required to construct a wall 11 m long, 3.5 m high and 40 cm thick, if the cement and sand used in the construction occupy $(\frac{1}{10}) t h$ part of the wall?