Question

How many bullets can be made out of a cube of lead, whose edge measures 22 cm, each bullet being 2 cm in diameter?

Answer 1

Edge of the cube $\left(r\right)=22cm\therefore Volume=a^3=(22{)}^{3}c{m}^3=22\times 22\times 22=10648c{m}^3$
Diameter of a bullet = 2 cm
$\therefore$ Radius (r) $=\frac{2}{2}=1cm$
$\therefore$ Volume of 1 bullet $=\frac{4}{3}\pi r^3$
$=\frac{4}{3}\times \frac{22}{7}\times 1\times 1\times 1c{m}^3=\frac{88}{21}c{m}^3$
$Numberofbullets=\frac{Totalvolume}{Volumeofonebullet}=\frac{10648\times 21}{88}=2541$