How many different sums can be formed with the following coins. A rupee, a $50$ paise, a $25$ paise, a $10$ paise and a $5$ paise.

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Solution

The correct option is B 31
A distinct sum will be formed be selecting either $1$ or $2$ or $3$ or $4$ or all $5$ coins.
The formula, we have is as follows $2^{n} - 1$ Therefor,e $2^{5} - 1 = 32 - 1 = 31$

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The number of different sums can be formed with the following coins a rupee a fifty paise a twenty five paise a ten paise a five paise?

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