How many electrons flow when a current of 5 amperes passed through a solution for 193 seconds?

6.022 \times 10^{23}

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6.022 \times 10^{22}

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6.022 \times 10^{25}

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6.022 \times 10^{21}

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Solution

The correct option is D $6.022 \times 10^{21}$
Current, I = 5 A
Time, t = 193 sec
We know that,
Q = It
Plug the values,we get
= 5 A × 193 s
= 965 Coulombs
Number of electrons = total charge / charge on 1 electrons
= $\frac{965}{1.6 \times 10^{- 19}}$
= $6.022 \times 10^{21}$ electrons

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How many electrons flow when a current of 5 amperes passed through a solution for 193 seconds?

The correct option is D 6.022×1021Current, I = 5 ATime, t = 193 secWe know that,Q = ItPlug the values,we get = 5 A × 193 s = 965 CoulombsNumber of electrons = total charge / charge on 1 electrons = 9651.6×10−19 = 6.022×1021 electrons

The correct option is D $6.022 \times 10^{21}$
Current, I = 5 A
Time, t = 193 sec
We know that,
Q = It
Plug the values,we get
= 5 A × 193 s
= 965 Coulombs
Number of electrons = total charge / charge on 1 electrons
= $\frac{965}{1.6 \times 10^{- 19}}$
= $6.022 \times 10^{21}$ electrons