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Question

How many grams of calcium carbonate are required to produce enough carbon dioxide which can convert 0.5 mole of sodium carbonate into sodium bicarbonate?
CaCO3CaO+CO2
Na2CO3+H2O+CO22NaHCO3

A
25 g
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B
50 g
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C
75 g
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D
100 g
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Solution

The correct option is B 50 g
CaCO3CaO+CO2
1 1 1
0.5 mol 0.5 mol
Na2CO3+H2O+CO22NaHCO3
1 1 2
0.5 mol 0.5 mol 1 mol
So, 50 g of
calcium carbonate is required to produce enough carbon dioxide.

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