Question

How many grams of oxalic acid is required to prepare M/100 solution in 200 ml.

Answer 1

Molarity = $\frac{1}{100}$

Therefore, $\frac{1}{100}$ = $\frac{\mathrm{m}}{126}\times \frac{1000}{200}$

m = $\frac{1}{100}\times \frac{126}{1000}\times 200$

= 0.252 g