How many moles of $K_{2} C r_{2} O_{7}$ can be reduced by 1 mole of $S n^{+ 2}$

$\frac{1}{3}$

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$\frac{1}{6}$

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$\frac{2}{3}$

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Solution

The correct option is A
$\frac{1}{3}$

It is clear from this equation that 3 moles of $s n^{2 +}$ reduce one mole of $C r_{2} O_{7}^{2 +}$ , hence 1 mol. of $S n^{2 +}$ will reduce $\frac{1}{3}$ moles of $C r_{2} O_{7}^{2 -}$ .

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Similar questions

How many moles of $K_{2} C r_{2} O_{7}$ can be reduced by 1 mole of $S n^{+ 2}$

K_{2} C r_{2} O_{7}

1

S n^{2 +}

K M n O_{4}

1

{K M n O}_{4}

1

K_{2} C r_{2} O_{7}

S n^{2 +}

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