Question

How many moles of lead (II) chloride will be formed from a reaction between $6.5$ g $PbO$ and $3.2$ g $HCl$ ?

• A. $0.011$
• B. $0.029$
• C. $0.044$
• D. $0.333$

Answer 1

The correct option is B $0.029$

Given as:

$n_{PbO}=\frac{6.5}{223}=0.029$ (atomic mass pf $PbO=223$)

$n_{HCl}=\frac{3.2}{36.5}=0.0877$ (atomic mass of $HCl=36.5$)

The reaction is,

$PbO+2HCl\to PbC{l}_2+H_{2}O$

In the given reaction $PbO$ will be limiting reagent because it is completely consumed and produce $0.029$ mol of $PbC{l}_2$.