Question

How many nuclei of ${}_{92}{U}^{235}$ should undergo fission, per second, to produce a power of $10MW$, if $200MeV$ of energy is released per fission of ${}_{92}{U}^{235}$?

• A. $3.12500$
• B. $3.125\times {10}^7$
• C. $3.125\times {10}^{17}$
• D. $3.125\times {10}^{27}$

Answer 1

The correct option is C $3.125\times {10}^{17}$

Given , the energy released per fission = $200MeV$

Power = $10MW$

We have the formula, $P=\frac{nE}{t}$

Where $P$ is the Power and $E$ is the energy released.

Substituting the above values in the given equation,

$\frac{n}{t}=\frac{P}{E}=$ $10$ X ${10}^6$/ $200(1.6$ X ${10}^{13})$

=$3.125$ X ${10}^{17}$