How much carbon dioxide will be formed in the reaction when 25 grams of glucose and 40 grams of oxygen are made to react?
Reaction: C6H12O6+6O2→6CO2+6H2O
A
24.2 g
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B
48.6 g
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C
36.7 g
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D
64.2 g
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Solution
The correct option is C 36.7 g C6H12O6+6O2→6CO2+6H2O
Moles of oxygen =4032=1.25 mol
Moles of glucose =25180=0.139 mol
Finding the limiting reagent: For oxygen=given molesstoichiometric coefficient=1.256=0.208For glucose=given molesstoichiometric coefficient=0.1391=0.139
Since, the ratio is minimum for glucose, it will be the limiting reagent.
1 mole of glucose produces 6 mol of CO2
0.139 mol will produce =61×0.139=0.834 mol of CO2
Mass of CO2=0.834×44=36.69g