Question

How much carbon dioxide will be formed in the reaction when 25 grams of glucose and 40 grams of oxygen are made to react?
Reaction: $C_6{H}_{12}{O}_6+6O_2\to 6C{O}_2+6H_{2}O$

• A. 24.2 g
• B. 48.6 g
• C. 36.7 g
• D. 64.2 g

Answer 1

The correct option is C 36.7 g

$C_6{H}_{12}{O}_6+6O_2\to 6C{O}_2+6H_{2}O$
Moles of oxygen $=\frac{40}{32}=1.25$ mol
Moles of glucose $=\frac{25}{180}=0.139$ mol
Finding the limiting reagent:
$\text{For oxygen}=\frac{\text{given moles}}{\text{stoichiometric coefficient}}=\frac{1.25}{6}=0.208$ $\text{For glucose}=\frac{\text{given moles}}{\text{stoichiometric coefficient}}=\frac{0.139}{1}=0.139$
Since, the ratio is minimum for glucose, it will be the limiting reagent.
1 mole of glucose produces 6 mol of $C{O}_2$
0.139 mol will produce $=\frac{6}{1}\times 0.139=0.834$ mol of $C{O}_2$
Mass of $C{O}_2=0.834\times 44=36.69\text{g}$