Question 62
How much is y4−12y2+y+14 greater than 17y3+34y2−51y+68?
Required expression is
y4−12y2+y+14−(17y3+34y2−51y+68)=y4−12y2+y+14−17y3−34y2+51y−68
On combining the like terms.
=y4−12y2−34y2+y+51y+14−68−17y3=y4−46y2+52y−17y3−54=y4−17y3−46y2+52y−54
So, y4−12y2+y+14 is y4−17y3−46y2+52y−54 greater than 17y3+34y2−51y+68.