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Question

Question 62

How much is y412y2+y+14 greater than 17y3+34y251y+68?

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Solution

Required expression is
y412y2+y+14(17y3+34y251y+68)=y412y2+y+1417y334y2+51y68
On combining the like terms.
=y412y234y2+y+51y+146817y3=y446y2+52y17y354=y417y346y2+52y54
So, y412y2+y+14 is y417y346y2+52y54 greater than 17y3+34y251y+68.


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