How much power is dissipated in a 50 ohm resistor supplied by 220 V source?

968 W

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978 W

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958 W

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948 W

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Solution

The correct option is A 968 W
By Joules's Law, Power $P = I^{2} R$
By Ohm's Law, $V = I R$
Hence, $P = V^{2} / R$
$P = 968 W$

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How much power is dissipated in a 50 ohm resistor supplied by 220 V source?

The correct option is A 968 WBy Joules's Law, Power P=I2RBy Ohm's Law, V=IRHence, P=V2/RP=968W

The correct option is A 968 W
By Joules's Law, Power $P = I^{2} R$
By Ohm's Law, $V = I R$
Hence, $P = V^{2} / R$
$P = 968 W$