Question

How much sulphur is present in an organic compound if on analysis is $0.53g$ of this compound gives $1.158g$ of $BaS{O}_4$?

• A. $10\%$
• B. $15\%$
• C. $30\%$
• D. $25\%$
• E. $20\%$

Answer 1

Answer: (C)

$30\%$

% of sulphur in BaSO${}_4$ =$\frac{32}{233}\times 100$ =13.7%

Therefore, Weight of sulphur in 1.158 g of BaSO${}_4$ =$\frac{13.7}{100}\times 1.158$= 0.158 g

Therefore, 0.53 g of compound gives 0.158 g of sulphur

Therefore, % sulphur in given compound =$\frac{0.158}{0.53}\times 100$ =30%