How much work is done in decreasing the volume of a gas by 2-4 - 10-4 m 3 at a constant pressure of 1 - 105 N - m 2 -

Work done= P Δ V = (1 × 10^5)(2.4 × 10^ 4) = 2.4 × 10 =24 J ...

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Byju's Answer

Standard XII

Physics

Area and Volume Expansion

How much work...

Question

How much work is done in decreasing the volume of a gas by $2.4 \times 10^{- 4} m^{3}$ at a constant pressure of $1 \times 10^{5} N / m^{2}$ ?

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Solution

Work done $= P Δ V$
$= (1 \times 10^{5}) (2.4 \times 10^{- 4})$
$= 2.4 \times 10$
$= 24 J$

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How much work is done in decreasing the volume of a gas by 2.4×10−4 m3 at a constant pressure of 1×105 N/m2?

Work done=PΔV =(1×105)(2.4×10−4) =2.4×10 =24 J

How much work is done in decreasing the volume of a gas by $2.4 \times 10^{- 4} m^{3}$ at a constant pressure of $1 \times 10^{5} N / m^{2}$ ?

Work done $= P Δ V$
$= (1 \times 10^{5}) (2.4 \times 10^{- 4})$
$= 2.4 \times 10$
$= 24 J$